03-Apr-2023
.
Admin
Hi Dev,
Here, I will show you how to works How to check if string is a json in PHP. you can see Validate json in PHP example. we will help you to give example of Check if string is a json or not. you can understand a concept of Json functions and operators in PHP.
json_decode($data, true) will return an object converted into an associative array, and then the is_array() function checks whether the object is an array or not. The json_last_error() returns the last error if there were any errors when json_decode() was invoked.
Example 1:
index.php
<?php
function json_validator($data) {
if (!empty($data)) {
return is_string($data) &&
is_array(json_decode($data, true)) ? true : false;
}
return false;
}
$data1 = '{"name":"uday", "email": "xyz@gmail.com"}';
$data2 = '{name:uday, email: xyz@gmail.com}';
echo "Result for data1: ";
echo (json_validator($data1) ? "JSON is Valid\n"
: "JSON is Not Valid\n");
echo "Result for data2: ";
echo (json_validator($data2) ? "JSON is Valid"
: "JSON is Not Valid");
?>
Output:
Result for data1: JSON is Valid
Result for data2: JSON is Not Valid
Example 2:
index.php
<?php
function json_validator($data) {
if (!empty($data)) {
@json_decode($data);
return (json_last_error() === JSON_ERROR_NONE);
}
return false;
}
$data1 = '{"name":"uday", "email": "xyz@gmail.com"}';
$data2 = '{name:uday, email: xyz@gmail.com}';
echo "Result for data1: ";
echo (json_validator($data1) ? "JSON is Valid\n"
: "JSON is Not Valid\n");
echo "Result for data2: ";
echo (json_validator($data2) ? "JSON is Valid"
: "JSON is Not Valid");
?>
Output:
Result for data1: JSON is Valid
Result for data2: JSON is Not Valid
I hope it could help you...
#PHP