Python Program to Check Leap Year?

Hi Dev,

Here, I will show you how to works Python Program to Check Leap Year. This tutorial will give you simple example of Program to check if a given year is leap year. I explained simply step by step Check if a Year is a Leap Year or Not in Python. Here you will learn Leap Year Program in Python. you will do the following things for Python Program to Check whether Year is a Leap Year or not.

Leap year program in python; Through this tutorial, you will learn how to check leap year program in python.

let's see below simple example with output:

Example 1: Python program to check whether a given year is a leap year or not

# Python program to check the given year is leap or not
 
n = input("Please enter year")
 
year = int (n)
 
if (( year%400 == 0)or (( year%4 == 0 ) and ( year%100 != 0))):
    print("%d is a Leap Year" %year)
else:
    print("%d is Not the Leap Year" %year)

Output:

Please enter year 2021 
2021 is Not the Leap Year 

Example 2: Leap year program in python using elif:

# Python program to check the given year is leap or not
 
n = input("Please enter year")
 
year = int (n)
 
if (year%400 == 0):
          print("%d is a Leap Year" %year)
elif (year%100 == 0):
          print("%d is Not the Leap Year" %year)
elif (year%4 == 0):
          print("%d is a Leap Year" %year)
else:
          print("%d is Not the Leap Year" %year)

Output:

Please enter year 2020 
2020 is a leap year   

Example 3: leap year program in python using nested if

# Python program to check the given year is leap or not
 
n = input("Please enter year")
 
year = int (n)
 
if (year % 4) == 0:
 if (year % 100) == 0:
   if (year % 400) == 0:
     print("{0} is a leap year".format(year))
   else:
     print("{0} is not a leap year".format(year))
 else:
   print("{0} is a leap year".format(year))
else:
 print("{0} is not a leap year".format(year))

Output:

Please enter year 2020 
2020 is a leap year   

Example 4: Python program to check leap year using function

# Python program to check the given year is leap or not 
# using math calender module in Python
 
#here import calender module
import calendar
 
n = input("Please enter year")
 
year = int (n)
 
# calling isleap() method to check for Leap Year
val = calendar.isleap(year)
 
if val == True: 
  print("% s is a Leap Year" % year)  
else:
  print("% s is not a Leap Year" % year)

Output:

Please enter year 2019 
2019 is not a Leap Year  

I hope it can help you...